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This equation is written on the basis of a unit mass, usually a gram or a kilogram, of solid adsorbent Thus n is the speciJic amount adsorbed, ie, the number of moles of adsorbate per unit mass of adsorbent Moreover, area A is defined as the specific surface area, ie, the area per unit mass of adsorbent, a quantity characteristic of a particular adsorbent The molar area, a A l n , is the surface area per mole of adsorbate The spreading pressure is the two-dimensional analog of pressure, having units of force per unit length, akin to surface tension It can be pictured as the force in the plane of the surface that must be exerted perpendicular to each unit length of edge to keep the surface from spreading, ie, to keep it in mechanical equilibrium It is not subject to direct experimental measurement, and must be calculated, significantly complicating the treatment of adsorbedphase equilibrium Since the spreading pressure adds an extra variable, the number of degrees of freedom for gasladsorbate equilibrium is given by an altered version of the phase rule For gasladsorbate equilibrium, n = 2; therefore,

Vince Lombardi assembled winning teams the same way mechanical engineers used to design the critical components of automobiles, through the cut-and-try approach The critical difference, of course, is that my father s raw materials were people,

Thus for adsorption of a pure species,

and two phase-rule variables, eg, T and P or T and n, must be fixed independently to establish an equilibrium state Note that the inert solid phase is counted neither as a phase nor as a species Recall the summability relation for the Gibbs energy, which follows from Eqs (118) and (1112):

Differentiation gives:

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10 This is the reason why argon may be solidified at a sufficiently low temperature 11 This is the reason why diamond is so hard 12 The triple point (A) represents the highest pressure at which the liquid can exist (B) is the lowest pressure at which the liquid can exist (C) represents the lowest temperature at which the vapor can exist (D) is 015 K higher than the melting point of the solid (E) is at a pressure of 1 atm 13 A sample of a pure liquid is placed in an open container and heated to the boiling point Which of the following may increase the boiling point of the liquid I The size of the container is increased II The container is sealed III A vacuum is created over the liquid (A) II and III (B) and III (C) III only (D) II only (E) I only 14 Which of the following best explains why 1-butanol, CH3CH2CH2CH2OH, has a higher surface tension than its isomer, diethyl ether, CH3CH2OCH2CH3 (A) (B) (C) (D) (E) the higher density of 1-butanol the lower specific heat of 1-butanol the lack of hydrogen bonding in 1-butanol the higher molecular mass of 1-butanol the presence of hydrogen bonding in 1-butanol

W H AT I T TA K E S T O B E # 1

d(nG) =

Comparison with Eq (14100) shows:

rather than metals and plastics; and that people change and interact in ways that steel, copper, and petroleum-based products don t He had to find the winning combination which, by the way, I don t think he ever thought of as a simple task But again, when the opening kickoff leaves the tee and the clock starts to run, the coach is more or less a spectator He learns whether he has or has not put together the winning combination In business, the winning combination is probably more elusive, in the sense that roles aren t so clearly delineated, there are usually far more players on the field, and hierarchies or divisional structures may get in the way of understanding what s working and not working and why it is or isn t working Maybe the bottom-line prescription here is a healthy dose of modesty The leader s role is to set the right play in motion and to more or less get out of the way of the players

This is the GibbsIDuhem equation for the adsorbate Restricting it to constant temperature produces the Gibbs adsorption isotherm:

15 Pick the answer that most likely represents the substances relative solubilities in water (A) CH3CH2CH2CH3 < CH3CH2CH2OH HOCH2CH2OH (B) CH3CH2CH2OH < CH3CH2CH2CH3 HOCH2CH2OH (C) CH3CH2CH2CH3 < HOCH2CH2OH CH3CH2CH2OH (D) HOCH2CH2OH < CH3CH2CH2OH CH3CH2CH2CH3 (E) CH3CH2CH2OH < HOCH2CH2OH CH3CH2CH2CH3 < < <

E xi d p , = 0

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